New Delhi: India hit one in a million ordeal on Wednesday after the team lost its 20th consecutive toss in ODIs in the second match of the series against South Africa in Raipur. This disappointing run started back at the 2023 ODI World Cup final against Australia and seems like a never ending thing as the Men in Blue hit a new low during the game.
The probability of this is one in more than a million with India becoming the only team in the world to face this nightmare. Meanwhile, South Africa won the toss and invited the KL Rahul-led side to bat first in the contest which will decide the fate of the series. If India win the encounter, they will pocket the series and if the Proteas emerge victorious, the series alive with the third and final match set to decide the outcome.
India play unchanged XI for Raipur ODI
Meanwhile Team India played an unchanged XI for the second ODI match at the Shaheed Veer Narayan Singh International Stadium. The side was expected to make some changes as per some reports earlier on Tuesday but they decided to go in with the same team which got them a victory in the series opener.
Teams
South Africa (Playing XI): Quinton de Kock(w), Aiden Markram, Temba Bavuma(c), Matthew Breetzke, Tony de Zorzi, Dewald Brevis, Marco Jansen, Corbin Bosch, Keshav Maharaj, Nandre Burger, Lungi Ngidi
India (Playing XI): Yashasvi Jaiswal, Rohit Sharma, Virat Kohli, Ruturaj Gaikwad, Washington Sundar, KL Rahul(w/c), Ravindra Jadeja, Harshit Rana, Kuldeep Yadav, Arshdeep Singh, Prasidh Krishna